The greatest thing about the Nintendo Switch Virtual Boy is how much it sucks

· · 来源:user资讯

这些词放在一份硅谷顶级风投的年度展望里,多少有些违和。过去二十年,风险投资的逻辑是逃离物理世界——越轻越好,越数字化越好,最好是纯软件,边际成本为零,可以无限复制。工厂、矿山、流水线,太重、太慢、太难标准化,不是VC该碰的生意。

3月4日国内黄金饰品价格对比显示,多数金店金饰价格较3月3日显著回调,多家报价已跌至1600元/克下方,较3日下跌逾50元/克。(财联社)

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Often people write these metrics as \(ds^2 = \sum_{i,j} g_{ij}\,dx^i\,dx^j\), where each \(dx^i\) is a covector (1-form), i.e. an element of the dual space \(T_p^*M\). For finite dimensional vectorspaces there is a canonical isomorphism between them and their dual: given the coordinate basis \(\bigl\{\frac{\partial}{\partial x^1},\dots,\frac{\partial}{\partial x^n}\bigr\}\) of \(T_pM\), there is a unique dual basis \(\{dx^1,\dots,dx^n\}\) of \(T_p^*M\) defined by \[dx^i\!\left(\frac{\partial}{\partial x^j}\right) = \delta^i{}_j.\] This extends to isomorphisms \(T_pM \to T_p^*M\). Under this identification, the bilinear form \(g_p\) on \(T_pM \times T_pM\) is represented by the symmetric tensor \(\sum_{i,j} g_{ij}\,dx^i \otimes dx^j\) acting on pairs of tangent vectors via \[\left(\sum_{i,j} g_{ij}\,dx^i\otimes dx^j\right)\!\!\left(\frac{\partial}{\partial x^k},\frac{\partial}{\partial x^l}\right) = g_{kl},\] which recovers exactly the inner products \(g_p\!\left(\frac{\partial}{\partial x^k},\frac{\partial}{\partial x^l}\right)\) from before. So both descriptions carry identical information;

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